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Buri Needs Help With Java Home work


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PAN Buri

Tue Mar 23 2010, 05:59PM

the five-o

Registered Member #245

Posts: 530

okay here is the prompt and i have no idea how to do this

Design and implement a program that reads a series of 10 integers from the user and prints their average. Read each input values as a string , and then attempt to convert it to an integer using the Integer.parseInt method. if this process throws a NumberFormatExceptio n (meaning that the input is not a valid number), print an appropriate error message and prompt for the number again. Continue reading values until 10 valid integers have been entered.

help a buri out buri will be most appreciative

Buri:
-Primeval being of Germanic myth. Formed from a salty block of ice,Buri was the father of Bor, who in turn fathered the gods Odin,Vili and Ve.

PAN Kanassa

Tue Mar 23 2010, 09:28PM

He Who Speaks Low

Registered Member #440

Posts: 2492

I know this isn't completely what you need, I think it's a start...been like 3 years since I've touched Java and tried learning other languages in between...




Scanner scanner = ne
w Scanner(System.in)
;



String[]
 numberString = new 
String[9]; //0-9 = 10 numberz

Int[]
 numberInt = new Int
[9]; //
the array to convert
 the strings into?



for (int i=0;
 i >= 9; i++) //
will ask you for a n
umber 10 times

{

try

{

    System.out.print
ln("GIMME NUMBER "
 + String[i+1] + ":
 "); //
ask for whatever num
ber you're on

    scanner[i]
 = scanner.nextLine(
); //accept input

}

catch (NumberFormatE
xception n)

{

    System.out.print
ln("
MUST ENTER A VALID N
UMBER!!!!!!");

}    

}

"To kill them teaches them nothing. You cannot exterminate them because from their seed comes more with greater hatred. Prison is nothing. Prison only makes hatred. That all our enemies should learn."

PAN Kanassa

Tue Mar 23 2010, 09:31PM

He Who Speaks Low

Registered Member #440

Posts: 2492

I left out the header stuff and the main class and what not, and I went brain dead as far as accepting the string and converting to an int. I know its like:

variable = Integer.parseInt(" string");

Good luck!


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